8) During a collision with a wall,the velocity of a 0.200-kg ball changes from 20.0 m/s...

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science physics

Answer 1

Answer #1

Q1.

Ans- (a) 26.7 N

Force applied is , F= change in momentum of ball / time duration

F= (mVf - m Vi)/ t

F= (0.200*12 - 0.200*20)/(60.0 * 10^-3)

F= - 26.7N

Hence magnitude of force applied is 26.7N.

So, correct option is (a) 26.7 N

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