Question

R10 3300 R5 4700 R9 2200 R3 -V1 36800 -20 V ER2 310000 Vx R6 8200

Answer 1

Selution Rio=33on R5 Ra 4ton 220 vo 1000 Z R₂ 68on - R6 82on Let Rake Resistor Rg and Rio are in parallel Combination of these resistors - Ra = (R9 | R) New, Rx R3, Ro are in series let Ry le - combination of these resistors Ry - Rat R3+ R6 • Ry = (Rq|| Re) + R₂ + R6. Ry = (33011220) + 680 +820 Ry = 1632

470 SR 20v Ry and R2 are in barallel. Let Rz lee Combination of these resistors. Rzz (RyllR2) = (1632 ||100) n. Rz= 620.06 a New Rz and Rs are in series I5 R5 . vit & Rz ... Is = V R5 + R₂ - 20. 620.06+ 470 Is = 0.01834 A RS tves VR, I&R Door 163225 Ry Zov - Ves = Is Rs = 0.01834 x 470 - [By ohn's Law]

Ives. = 8.62v Applying current division rule in above circuit. In = Is x Ry - 0.01834 x 1632 - Rat Ry 1000 + 1632 ---I2 0·01137 A :: VR2 = I2 R₂ = 0.01137x1000 (By ohm's law] [UR2 = 11:37 V # Ilo Rio - Is R5 0 Ty Puma ? & URE - Ra & R23. ve xurg 14 - VR 20V - my 13 VRG & Xb ly current flows through Rz and Ro resistors - T-I3 = I current law at hode ① - Is = Izt ly Iy = 0.01834-0.01137 - Jy = 6.97816? A I3 = 16 = 6.978103A VR3= I3 R3 = 6:9780² x 680 = 4•7396 V Vez= 4.7396 v

VR6 = I6 R6 = 6.97810 3 x 820 [VR6 = 5.7154 V By current division rule Ijo - Iyx Rq Rq+Rio Iso = 6.97X163 x 220 220+ 330 Ilo = 2-788 x103 A .. VRI = I lox Rio = 2.788 x10²x330 (Vaso = 0.92004 v 1 Applying kirchaff's worrent law at hode @ - Jy = Iq + Ilo . I q = 6.9780² - 2.788x103 Iq = 4,182x103A _VRq - Igx R9 = '4.182x/6?x220 TVeq = 0.92004

> + 20v VR2 R3 from the above circuit ka - VRzt VR6 Vx= 4.7396 +5.7154 Tx=10.455 V