A monochromatic light with a wavelength lambda=600nm passes through a single slit which has a width...
A monochromatic light with a wavelength lambda=600nm passes through a single slit which has a width of 0.800mm.
a.) What is the distance between the slit and the if the first minimum in the diffraction pattern is at a distance 1.00mm from the center of the screen?
b.) Calculate the width of the central maximum.
Please show all work and explain the concepts behind this if you can.
Homework Answers
lamda = 600 nm
d = 0.8 mm = 0.0008 m
y1 = 1.00 mm = 0.001 m
a) let L is the distance between the slit and screen
for first minimum, y1 = lamda*L/d
L = y1*d/lamda
= 0.001*0.0008/(600*10^-9)
= 1.33 m
b) width of the central maximum, delta_y = 2*lamda*L/d
= 2*600*10^-9*1.33/0.0008
= 0.00200 m
= 2.00 mm
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