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Sulphur trioxide is formed by the reaction between sulphur dioxide and air (more correctly oxygen) in...

Sulphur trioxide is formed by the reaction between sulphur dioxide and air (more correctly oxygen) in a catalytic reactor, according to the unbalanced equation The reaction conditions give a 50% conversion when stoichiometric quantities of the reactants are used. (a) Balance the equation. (b) Calculate the composition (on a mole fraction basis) of the final mixture leaving the reactor.

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Answer #1

The balanced chemical equation is

2SO2 + O2 -----> 2SO3

According to the question, the reaction gives 50% conversion when stoichiometric quantities of the reactants are used. In other words only half of the reactants undergo reaction to give the product.

This means if 2 moles of SO2 and 1 mole of O2 are added, half of them will react to give 1 mole of SO3. while 1 mole SO2 and 0.5 mole O2 will remain unreacted and will leave the reactor.

Thus composition of the final mixture leaving the reactor would be

n(SO2 )= 1 , n(SO3) = 1, n(O2) = 0.5

Total number of moles = 2.5

Mole fraction of SO2 = 1/2.5 = 0.4

Mole fraction of SO3 = 1/2.5 = 0.4

Mole fraction of O2 = 0.5/2.5 = 0.2

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