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given 1 kilogram of liquid water is converted into steam at 100 degrees celcius at the pressure of 1 atm. the initial liquid volume of 1 e-3 m3 boils into a steam volume of 1.671 m3. find the following calculations

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Answer #1

Ans. 1:  Work done (W)

  Work done = P(½-%) = 1.013 × 105 × (1.671-0.001) 1.691 × 105Joules

Ans. 2:   Heat supplied (Q)

Heat supplied = mass × heat of vaporization = 1 × 2256 × 103-2256 × 10,oules-2256 k

Ans. 3:   Change in internal energy Δυ

According to first law of thermodynamics,

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  22.56 × 105- 5ー20.869 × 105 Joules AU = Q _ W 1.691x 10

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