The vector <8, -6> when written in component form, would be y = .

Question

Question

math trigonometry

Answer 1

Answer #1

Answer & Cirers vector C8,-6) Componest from will be X,=0, X₂ = 8 Y=0 , I 2 = -6 And Y2 - 4 vector will be fromed by X-X, her

Answer 2

Similar Homework Help Questions

Find the component form and the magnitude of the vector v. -10 -8 -6 -4 -2...

Find the component form and the magnitude of the vector v. -10 -8 -6 -4 -2 2 4 6 8 (-9,-2) Need Help? Read It Watch It -/2 POINTS LARAT10 8.3.020. Find the component form and the magnitude of the vector v. Initial Point Terminal Point (-2,5) (5, -19) Need Help? Read It Watch It
2) (a) Show that the x-component of the Lorentz force, when written in terms of vector...

2) (a) Show that the x-component of the Lorentz force, when written in terms of vector potentials as we did in class, can be expanded and then recast as + d where U = qV qr . A. Thus, show that Lagrange's equations still hold so long as U is taken to have this form, and that the Lagrangian for a non-relativistic particle in an electric and magnetic field can be written as equation (7.104) in the text. a charged...
2) (a) Show that the x-component of the Lorentz force, when written in terms of vector...

2) (a) Show that the x-component of the Lorentz force, when written in terms of vector potentials as we did in class, can be expanded and then recast as o where U q-qA. Thus, show that Lagrange's equations still hold so long as U is taken to have this form, and that the Lagrangian for a non-relativistic particle in an electric and magnetic field can be written as equation (7.104) in the text. (b) Show from this Lagrangian and the...

a) Show that x-component of the Lorentz force, when written in terms of vector potentials as...

a) Show that x-component of the Lorentz force, when written in terms of vector potentials as we did in class, can be expanded and then recast as where Thus show that Lagrange’s equations still hold so long as U is taken to have this form, and that the Lagrangian for a non-relativistic particle in an electric and magnetic field can be written as equation (7.104) in the text: b) Show from this Lagrangian and the analysis in Section 7.8 that...
Vector A has a negative x component 3.30 units in length and a positive y component...

Vector A has a negative x component 3.30 units in length and a positive y component 2.02 units in length (a) Determine an expression for A in unit-vector notation. j) units (b) Determine the magnitude and direction of A magnitude direction unit(s) o counterclockwise from the positive x axis (e) what vector B when added to vector A, gives a resultant vector with no x component and a negative y component 4.14 units in length? j) units
Vector B (a displacement) has an x-component of -2.50 m and a y-component and a y-component...

Vector B (a displacement) has an x-component of -2.50 m and a y-component and a y-component of +4.20 m. What are the magnitude and direction of vector B?

Find the component form of vector with initial point (-6, 2) and terminal Point (7,-3)

Find the component form of vector with initial point (-6, 2) and terminal Point (7,-3)
Find x-component of vector a? =(2.0m/s2 , - y-direction).Find y-component of vector a? =(2.0m/s2 , -...

Find x-component of vector a? =(2.0m/s2 , - y-direction).Find y-component of vector a? =(2.0m/s2 , - y-direction).
1) What are the x and y components of this vector? x-component: 2) y-component 3)The x...

1) What are the x and y components of this vector? x-component: 2) y-component 3)The x component of a vector is 12.5 m and the y component of a vector is 25 m. What is the magnitude and direction (with respect to the positive x-axis) of this vector? magnitude: 4)direction: A vector has a magnitude of A = 16.5 m and makes an angle of 0 = 5.4 ° with the negative x-axis. A

A) Find the x -component of vector C⃗ B) Find the y -component of vector C⃗...

A) Find the x -component of vector C⃗ B) Find the y -component of vector C⃗ Can you help me in this question? Thanks all. You are given vectors A= 4.5 i – 6.0 j and B=- 3.6 î+ 7.4 j. A third vector Č lies in the xy-plane. Vector C is perpendicular to vector A and the scalar product of C with B is 15.0.