Question

Thank you!

= v 552 SED AaBbCcI AaBbci AaBbci AaBbCcl 1 Normal 1 No Spac... Heading 1 Heading 2 Paragraph Styles 1. Identify the types of intermolecular forces that would be present in a pure sample of each substance for the following pairs of molecules. It may help to draw Lewis structures in some cases (a) Hexane: CH3CH2CH2CH2CH2CH3 Triethylamine: (CH3CH2)2N (b) Butanol: CH3CH2CH2CH2OH Diethyl ether: CH3CH2OCH2CH3 (c) Hydrogen sulfide: H2S Ammonia: NH3 Oxygen: 02 (d) Chlorine: Cla 2. For each pair of molecules (the same as the ones in question 1), circle the substance that you would expect to have the higher boiling point. Briefly justify each choice. Havana Triethylamine Focus 16 - SAMSUNG

Answer 1

. Dut Due to electronegative as Hexane : CH, CH, CH.CH1, CH-CH : It is a fully non polar. Compound so na only london dispersion forces will be . . . operating Triethylamine & (CH₂ CH2 N or any but y rimogen atom, molecule Cis polar and · L i s t , hence dipole - dipole interactions will · play alsó dipole' induced dipole internet will be present. (b) Butanol { CH₂ CH₂ CH CH OH): Due to presence of -OH group butanol is capable of forming hydrogen bond: So hydrogen bonding will be major intermolecular force operating : Diethyl ether (CH3 CHLOCH CH): Due to orygen molecule is polar, hence dipole - dipole forces will operate.. () Hydrogen sulphide (Hbs)! si Molecule is angular and sis more eleckonegative than ti so it is a polar molecule and hence dépole - dipole forces will operate. 4 An Na ( 4 ) : Ammonia is capable of forming H-bond. " So hydrogen bonding will operate d ) chlorine : (2 : 2+ is a nonpolar molecule so only London forces or Lispersion forces operate. Oxygen (O2) : et is also a non polar molecule so only london or dispession forces will play.