Question

Calculate the electric field(magnitude and direction) at the center of a square 52.5 cm on a side if one corner is occupied by a - 38.4 μC charge and the other three are occupied by - 27.8 μC charges.

Answer 1

Given that (- 27-847 k 58.5cm IC (-27-84c) 0 B 227-84)... ( 738.4 18-44c) is to u un we cleary known that Electric field due to positive charge is away from charge t h e towards negative charge is due to Electric field charged charge sot Since we were centre so Reference. asked centre cos calculate is our Electric field Total force at point of.

Since Charge at B and The Resultant of these charge at D ave Sproof so. two forces (only due to B and D) is nullified (200) Electric Field au the streetal due So we have · to consider to only A and C so. To We known that .. point charge at a ho. Elechic point field due to is given by €22,92) Te Q (21. My 1 @ + (x+41) ĝ 7 LE CTER here and Electris field Ē is rector ēs (-x) @ + (92-4)

the The direction of directian of ē ( Electric field) is in Rooi Now consider the entire system of square charges is placed in co-ordinate systems such that origin is at ^ (Charge 1 ) ) (52.5, 52-5) VY 10,52.stt DE4 Pro) (52.540) Charces at A (-38.4c) O . at B 6-27-8 J4C) o f Centre of square ABCD is o (26:25;26:25) at a f2784C) o, at D (-27-8 uc) on According to the formulae, O he have. Resultant q only A and c to be calculated. So. now due to A Charge (-384c) at 04.) point o (centre Ros, 26:25)) t2 G ACC

e - ՖՐԿ xis էր (, ((չcs. 0) + (118-03) ( ((Ձեշը՚ (20155 * = - 38-4 X15․ | Ձ 6.25 + 16-25 տ) - ։ | Կո€o ( (202) ( )} . ՛ի For air = 720: -38.4y+Ծ ԷՐ 2 + 1 1 1 . Պxto? | T (-- 20- }{" ՆՆԵԵԵՆՆՆՆՆՆՆ, Այս e - - 196» «14-4)). բ- -177-որ (1+ 3)-41 _ (@ . «• 18 + 4);am : ( է Now Due to «+ (53. , 53r) a n ՝ charge (.-270846) point o (arhic (214, 24 25 ) - | - - IT , , - 24. 1 ro * (ka tar- 5:•• ) + + 24 • 30- St․r) , * - () as aci°F (36․ 15) -՞ - 27,8 x 16 + 7 - 34, 356 + 24 - ՉՄ ՝ | - r *, | Ն՝ (ՀՀ «ՀՐ):

Ez - 128.59 (dt ) vion] Net Electric field at "center of aquare Due to charges or Os is Eneta Ez + E . 128,39 (+ ĝ) - 177,35(ît + ģ) renet - - 48.96 cât } } ] Enet a -48.967 - 48.96 ŷ Magnitude . 98.965€ 148.965 48.96 r2 = 69.22 V/en. Tom Direction vector l Emekl Manitude