147N+42He=178O+?? a. 10n b. 11H c. 42He d. 0-1e

Question

Question

¹⁴₇N+⁴2He=¹⁷₈O+??

a. ¹₀n

b. ¹₁H

c. ⁴₂He

d. ⁰_-1e

science physics

Answer 1

Answer #1

11H

mass number on left = mass number on right

14 + 4 = 17 + A

A = 1

atomic number of left = atoimic number on right

7 + 2 = 8 + Z

Z = 1

so 11H

Answer 2

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