We know that, Magnetic force is given as:
F= l(i X B) where, l: Length of the current carrying material and,
i: current B: Magnetic field.
Direction of force can be determined from right hand thumb
rule.
Hense, from Right hand thumb rule, Force on the conductor is in
downward direction.
Hense, upper edge is at higher potential.
B is a uniform magnetic field. Current flows to the right. Is the upper or lower...
Within a uniform magnetic field B, a straight wire is carrying current in the direction shown in this figure. The direction of this uniform magnetic field is denoted by the blue dots. (Think about what these dots means. This was taught in my lectures.) B. What is the direction of the magnetic force acting on this current-carrying wire? The magnetic force points: A to the right: B. out of the page; C. Into the page: D. to the left; O...
The steady current carrying rectangular conductor is placed in a
uniform magnetic field as shown in
5. The steady current carrying rectangular conductor is placed in a uniform magnetic field as shown in Figure 3. a) What is the voltage difference, V between the side (shown with w) of the conductor in terms of the parameters given in Figure? b) What would be the voltage difference, V between the side of the conductor if B=0? L w h 1 B...
the answers are:
a. 0.24, current flows left to right
b. 0.24, current flows right to left
c. 0.41, current flows tight to left
d. 0.65, current flows left to right
e. 0.65, current flows right to left
A horizontal length of current-carrying wire is suspended from two identical flexible leads that are under tension due to the weight of the wire. The wire is oriented at right angles to a uniform magnetic field that has a magnitude of 3...
a/2 Once more, consider the two conductor configurations in a uniform magnetic field with strength B. Which statement is true? The magnetic flux change is dpB/dt - Bav for the left example. For the example on the right it is only half of that. The magnitude of the induced current is the same in both cases. The larger the speed v, the faster the increase of the magnetic field
The right edge of the circuit in the figure extends into a 50 mT
uniform magnetic field.What are the magnitude and direction of the
net force on the circuit?leftrightupdown
A proton and an electron traveling at the same speed enter a uniform magnetic field. The velocity vector of each particle is perpendicular to the magnetic field. What will be ratio of the radii of their circular orbits (rproton/relectron)? O 5.5E-4 O 0.5 O 1.0 O 1800 O 3600 A horizontal length of current-carrying wire is suspended from two identical flexible leads that are under tension due to the weight of the wire. The wire is oriented at right angles...
In what direction is the magnetic force on a current-carrying wire if the current flows to the left (-x) and the uniform magnetic field points out of the page? a. right b. left c. up d. down e. into the page f. out of the page
A flat, 172-turn, current‑carrying loop is immersed in a uniform magnetic field. The area of the loop is 6.55 cm2 and the angle between its magnetic dipole moment and the field is 30.5∘. Find the strength B of the magnetic field that causes a torque of 1.23×10−5 N⋅m to act on the loop when a current of 2.73 mA flows in it.
A uniform magnetic field B=5.210 T is perpendicular to the plane of the paper (into the page). The current-carrying wire of value I = 2.000A (directed to the right) with length L=0.5000m perpendicular to the magnetic field and current is going from left to right. Find the magnitude of the magnetic force (in Tesla) on the wire. A. 5.210T B. 10.42T C. 0T D. Can not be determined Please show work!
The picture shows a rectangular current-carrying loop in a uniform magnetic field that is directed right. The loop is free to rotate about the axis shown as the dashed line in the top view. (a) Select all the correct statements about this situation from the list below. As seen from the side view, the initial net torque on the loop is clockwise As seen from the side view, the initial net torque on the loop is counterclockwise As seen in the top view, the...