The Ka of propanoic acid (C2H5COOH) is 1.34 × 10-5. Calculate the pH of the solution AND the concentrations of C2H5COOH AND C2H5COO– in a 0.323 M propanoic acid solution at equilibrium. Please explain each step in detail.
C2H5COOH ---> C2H5COO– + H+
initial 0.323 0 0
at equilibrium
0.323-x
x x
kA = [C2H5COO– ][H+]/[C2H5COOH]
1.34 * 10^(-5) = x^2/(0.323-x)
x = 0.0021 M
[C2H5COO– ]= 0.021 M [H+] = 0.0021 M
[C2H5COOH] = 0.323-0.0021 = 0.3209 M
The Ka of propanoic acid (C2H5COOH) is 1.34 × 10-5. Calculate the pH of the solution...
The Ka of propanoic acid (C2H5COOH) is 1.34 × 10-5. Calculate the pH of the solution and the concentrations of C2H5COOH and C2H5COO– in a 0.421 M propanoic acid solution at equilibrium.
The ?aKa of propanoic acid (C2H5COOH)(C2H5COOH) is 1.34×10−5.1.34×10−5. Calculate the pH of the solution and the concentrations of C2H5COOHC2H5COOH and C2H5COO−C2H5COO− in a 0.517 M0.517 M propanoic acid solution at equilibrium.
Determine the pH of a 4.79 x 10^-4 M solution of propanoic acid, C2H5COOH. The Ka of propanoic acid is 1.34 x 10^-5.
The K₄ of propanoic acid (C₂ H₃ COOH) is 1.34 × 10-3. Cakalate the pH of the solution and the concentrations of C₂H₃COOH and C₂H₃COO- in a 0.379 M propanoic acid solution at equilibrium.
You are asked to prepare 100 mL of a propanate/propanoic acid buffer with a pH of 5.5. Ka of C2H5COOH=1.34*10^-5 If you used 40 mL of a .1 M C2H5COOH solution, what volume of a .4 M Na C2H5OO solution would you need to prepare the solution?
Calculate the volume of 0.531 mol/L propanoic acid (C2H5COOH, pKa = 4.88) that must be added to 60.0 mL of 0.450 mol/L calcium propanoate (Ca(C2H5COO)2) to prepare a buffer solution with a pH of 5.00.
Calculate the volume of 0.531 mol/L propanoic acid (C2H5COOH, pKa =
4.88) that must be added to 60.0 mL of 0.450 mol/L calcium
propanoate (Ca(C2H5COO)2) to prepare a buffer solution with a pH of
5.00.
Calculate the volume of 0.531 mol/L propanoic acid (CH-COOH, PK, -4.88) that must be added to 60.0 mL of 0.450 mol/L calcium propanoate (Ca(CH.COO).) to prepare a buffer solution with a pH of 5.00. 77 mL 98 mL 136 ml 68 ml 220 mL 11...
1) A 1.31 L buffer solution consists of 0.301 M propanoic acid and 0.159 M sodium propanoate. Calculate the pH of the solution following the addition of 0.073 mol HCl. Assume that any contribution of the HCl to the volume of the solution is negligible. The Ka of propanoic acid is 1.34×10−5. pH = 2) Consider Kc for the following equilibrium given the info below. 2SO3(g)⇌2SO2(g)+O2(g) 0.20 mol SO3 is placed in a 1.00 L vessel at a high temperature...
1. 50.00 mL of 0.1000 M propanoic acid (CH3CH2COOH – Ka = 1.34 X 10-5) is titrated with 0.2000 M KOH. Calculate the pH at the following points in the titration: 1) Initial pH – no KOH has been added. 2) 5.00 mL of KOH has been added. 3) 12.50 mL of KOH has been added. 4) At the equivalence point. (Calculate the volume of KOH to reach the equivalence point & identify a good indicator.) 5) Provide a sketch...
The pH of a 0.20 M propanoic acid (CH3CH2COOH) solution is 2.79. Calculate the Ka of propionic acid.