Question

D . Select the lightest-weight steel wide-flange overhanging beam from Appendix B that will safely support the loading. Assume the support at A is a pin and the support Jo now = 12 ks: at B is a roller. The allowable bending stress is allow = (see email data) Zaves IU KS and the allowable shear stress is allow --- 14 ksi. P=11 hip 8t 44 y. Selected beam section is: W X P (see email data for value of P)

Answer 1

Given: Tay = 12ksi, Talu = luksi, P = 11kip To Catulate: Select the light-weight steel wide ange(w) RA+RB = 2x11.0 RA+R₂ = 22 RB X 8 - 11x10 - 11X14 = 0 RB x 8 = 264 RB = 33 kup RA=-1|kip Drawing Shear Force diagram 1 0<x< 4 3) 6 <x514 F= 11 F -11 3 4 <x<6 = 22

- 2 2 2 22 kip allkip Bft att ft -11 kep dM-F ( Here F= shear Force, Mc Bending da moment F=0 dm =0 So Mu max, when F=o peat point B. (Mg) max 8 x 11 kup oft 8 max = 88 kepitt

So for B) = Moxy (B max au = 12ksi lift=12in Z= 86xx Z= BB on Now tendency of failure in Tau is lesser ,so we will use only bending stress. So From Appendix B 5 W12465 - Answer.