What volume would be occupied by 3.5 mol of oxygen gas at a pressure of 768 mmHg and a temperature of 25 degrees Celsius?
Given:
P = 768.0 mm Hg
= (768.0/760) atm
= 1.0105 atm
n = 3.5 mol
T = 25.0 oC
= (25.0+273) K
= 298 K
use:
P * V = n*R*T
1.0105 atm * V = 3.5 mol* 0.08206 atm.L/mol.K * 298 K
V = 84.697 L
Answer: 84.7 L
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