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Score: 175/250 20/25 answered • Question 6 Assume that the readings at freezing on a batch of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested. Find P11, the 11-percentile. This is the temperature reading separating the bottom 11% from the top 89%. Round to 3 decimal places. P11 = Submit Question

Answer 1

solution 67 The readings are normally destruibuted with meanzo's and standared deviation = 1.80 e. Let X be the readings of the selected thermometers so, 2- Xogle N(0,3) P(x 4 = 8• 11 - 11 → PC ou Sk.) -0.13 >> P125 * 10) = 0. → PLZ52) = 0.11 = $(x) = 0.18 = x= [(0.14) => x= -1.227 from the standared normal 7 Area Table. ii P44= -1.227

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