Question

10. Solve the equation below on the interval (0.2T). cos2x = V3

Answer 1

16) Cos 27 V2 we Can Split dhis into 2 Passible (ases V3/2 Cos (27) = Cos-! Cos 21-2X = 22 =-> 27-2x =76 periuds adding by 2x = 5/6+2na, nez 29-2x = 7/6+20a, nez 29-76-20g = 2X Min+na, nez

(2 +na, nez Since nez, Then -ng =na] - (1) interual 0,27) In In put 11 n+0 nlin => in Put n:1 137 Th 237 1)

19 Put n= 2, ho Interval 6, 19) ared values the" in Ther 137/12, 237/12) ("in, Ali2i