the net force on the charge
= F= qv*B
= 1.28*10^-2 = 3.70*10^-6 * 5*B SIN[35.3]
= 1197 = B
AND THE DIRECTION OF FORCE = OUT OF THE PLANE
WE FIND THE CROOS PRODUCT OF THE VELOCITY AN THE MAGNETIC FIELD WHICH IDS OUT OF THE PLANE
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