Question

Calculate the torque (magnitude and direction) about point O due to the force F⃗  in each of the cases sketched in the figure (Figure 1). In each case, the force F⃗  and the rod both lie in the plane of the page, the rod has length 4.00 m, and the force has magnitude 16.0 N .

Answer 1

Torque direction of torque is given by right hand rule Case a) part (A) 0 Part B direction out of the page Case b)

Part c 0 20 F- 16 N angle between vector I and F #2 180-120 60. t IFsin 60 t-4 x16x sin 60 -32 x V3N m 32 x 3 55.426N m Part D direction out of the page Case c) Part E

0 3o τ = 1 Fsin 30 τ=4×16×sin 30 = 32 τ=32N·m Part F direction out of the page Case d) Part G) 60 0

τ--Fsin 60 τ 2x16xsin 60 16 x V3 Part H direction into the page Case e) Part-l 60° 0 τ=0 Part J

line of action of force passes through the point 'o'so the torque is zero Case f) Part K) Part L line of action of force passes through the point 'o'so the torque is zero