Question

1.2 moles of ideal gas in a cylinder are compressed isothermally from an initial pressure of 120 kPa and a volume of 0.025 m3 to a final volume of 0.004 m3. Calculate the temperature and the final pressure of the gas; and also estimate the work done on the gas.

Answer 1

MALL ..Ininal Solution Iso thermal Compression ( constant Temprature) na moles 1.2 moles of Ideal gasi magas constant - Pressure (B) = 120kpa =) 120 Initial volume (VD) 0.025 m3 final volume (12) = 0.004 m3. (Tempratnes T=? R = 8.314 J mal (W) Work done= ? from Boylew law : PV, PzV2 . 120x16x0.025 (m3) = P2 (Pa)x0.004(m3) P2 = 120X10 X0-075 6.25 0.oon (m) 75 0000 Parlane , T 750kPa Bokea for Isothermal Compression : Work done We are encore wo 8.31465/mic from Ideal gas equanich. pro MRT. CTeepzahm) Т? Ру Гуч Сот аке Р., v, Y P.,N2 L whatever you wish to take T. 20410X0.025 m3 MR. pa 14433485 Same Temperature will as (Pa = 1 mm) (mou), 2 x 8-314 Toron T, 12027.9044 0.025) ºk T= 300.69°k Am. - Constant Temprature

OX For Isothermal process work done is : Leme => W2 MRT en 2) We 1.2 Andle) 8.314 I imp 120x4opq7 x 300.69 0 W? 2999923(5) X61.832) W 2-5495.860J W2-5,495 KJ 1 Aus. 159 *183 Pa] X-
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