
2. The manager of a local restaurant wants to estimate the percentage of the restaurant's patrons...
19A telecommunications company wants to estimate the proportion of households that would purchase an additional telephone line if it were made available at a substantially reduced installation cost. Data are collected from a random sample of 500 households. The results indicate that 160 of the households would purchase the additional telephone line at a reduced installation cost. Complete parts (a) and (b) below. a. Construct a 99% confidence interval estimate for the population proportion of households that would purchase the...
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A History professor at a local community college wants to estimate the percent of college students that cheat on online assessment. Out of 100 college students sampled, 39 had cheated. Based on this, construct a 99% confidence interval for the proportion p of college students that have cheated in his history class. Make sure to express your answers as decimals, to three places. Use the point estimate and margin of error to express the same answer. Give your...
uan wants to estimate the percentage of people who will vote for issue A on the next election. He surveys 150 Individuals and finds that 81 will vote for issue A. Find the margin of error for the confidence interval for the population proportion with a 90% confidence level. Z0.10 Z0.05 0.0251 z0.01 0.005 1.2821 1 :645| 1.960||2.326|2.576 Use the table of common z-scores above. Round the final answer to three decimal places
uan wants to estimate the percentage of...
The manager of a large supermarket wants to use a 95 percent confidence interval to estimate the true proportion of the market's customers who buy cookies from the market. After collecting data from a random sample of customers, he calculates the confidence interval to be (0.236,0.282)(0.236,0.282). Which one of the following statements is true? Select one: A. The confidence interval provides convincing evidence that more than 25 percent of the market's customers buy cookies from the market. B. There is...
A fast food restaurant recently added a new sandwich to its menu. To estimate the popularity of this sandwich, a random sample of 43 customers who ordered the sandwich were surveyed. Each of these customers were asked to rate this sandwich on a scale of 1 to 100. The manager used the resulting data to calculate a 95% confidence interval for the mean rating of the new sandwich. 95% confidence interval: (57.65, 66.84) (a) Identify the parts of this confidence...
The owner of a local golf course wants to estimate the difference between the average ages of males and females that play on the golf course. He randomly samples 9 men and 10 women that play on his course. He finds the average age of the men to be 44.71 with a standard deviation of 9.971. The average age of the women was 46.91 with a standard deviation of 10.972. Construct a 95% confidence interval to estimate the difference of...
Eric wants to estimate the percentage of elementary school children who have a social media account. He surveys 450 elementary school children and finds that 280 have a social media account. Identify the values needed to calculate a confidence interval at the 99% confidence level. Then find the confidence interval. z0.10 z0.05 z0.025 z0.01 z0.005 1.282 1.645 1.960 2.326 2.576 Use the table of common z-scores above. Round the final answer to three decimal places. p1=
Jane wants to estimate the proportion of students on her campus who eat cauliflower. After surveying 15 students, she finds 2 who eat cauliflower. Obtain and interpret a 95% confidence interval for the proportion of students who eat cauliflower on Jane's campus using Agresti and Coull's method. Construct and interpret the 95% confidence interval. One is 95% confident that the poplulation of students who eat cauliflower on janes campus is between___and ____? *Use the corrent z store interval for 95%...
The owner of a local golf course wants to estimate the difference between the average ages of males and females that play on the golf course. He samples a group of men and women and then uses the sample statistics to calculate a 99% confidence interval of (6.28, 21.77). This interval estimates the difference of (the average age of men - the average age of women). What can we conclude from this interval? Question 8 options: 1) We are 99%...
The owner of a local supermarket wants to estimate the difference between the average number of gallons of milk sold per day on weekdays and weekends. The owner samples 24 weekdays and finds an average of 242.462 gallons of milk sold on those days with a standard deviation of 36.143. 28 Saturdays and Sundays are sampled and the average number of gallons sold is 335.717 with a standard deviation of 43.83. If a 95% confidence interval is calculated to estimate...