Question

PrintArray vi Create a class called PrintArray. This is the class that contains the main method. Your program must print each of the elements of the array of ints called aa on a separate line (see examples). The method getArray (included in the starter code) reads integers from input and returns them in an array of ints. Use the following starter code: //for this program Arrays.toString(array) is forbidden import java.util.Scanner; public class PrintArray { static Scanner in = new Scanner(System.in); public static void main(String[] args) { int[] ag = getArrayO; //at this point aa has been populated with integers taken from //standard input. It could be any number of ints. ///////////////////////your code starts here (don't change anything else) ///your code ends here //expects a line containing ints separated by spaces //returns array of ints containing the ints found public static int[] getArray() { String nums; int numint = 0; int xx; System.out.print("enter ints: "); nums = in.nextLine(); Scanner scan = new Scanner(nums); while (scan.hasNextInt() { XX = scan.nextInt(); numint++; int[] intArray = new int[numint]; scan = new Scanner(nums); for (int i = 0; i < numint; i++) { intArray[i] = scan.nextIntO; scan.closeO; return intArray;

Answer 1

Code:

import java.util.Scanner;

public class PrintArray{

               static Scanner in = new Scanner(System.in);

               public static void main(String args[]){

                             

                              int[] aa = getArray();

                              //code to print each element of aa on a separate line

                              for(int i = 0; i < aa.length; i++)

                                             System.out.println(aa[i]);

                              //the code ends here

               }

               public static int[] getArray(){

                              String nums;

                              int numint = 0;

                              int xx;

                             

                              System.out.print("enter ints: ");

                              nums = in.nextLine();

                             

                              Scanner scan = new Scanner(nums);

                             

                              while (scan.hasNextInt()){

                                             xx = scan.nextInt();

                                             numint++;

                              }

                              int[] intArray = new int[numints];

                              scan = new Scanner(nums);

                             

                              for(int i = 0; i < numint; i++)

                                             intArray[i] = scan.nextInt();

                             

                              return intArray;

               }

}

- import java.util.Scanner; public class PrintArray static Scanner in = new Scanner (System.in); public static void main(String args[]) { int[] aa = getArray(); // code to print each element of aa on a separate line for (int i = 0; i < aa.length; i++) System.out.println(aa[i]); //the code ends here public static int[] getArray ( ) { String nums; int numint = 0; int xx; System.out.print("enter ints: "); nums = in.nextLine(); Scanner scan = new Scanner (nums); while (scan.hasNextInt () { xx = scan.nextInt (); numint++; int[] intArray = new int[numint]; scan = new Scanner (nums); for (int i = 0; i < numint; i++) intArray[i] = scan.nextInt (); return intArray;

Output:

run: enter ints: 10 20 30 40 50 10 20 30 50 BUILD SUCCESSFUL (total time: 15 seconds)