Question

-n Avogadro's Law and Molar Volume at STP (1.00 mole of any gas-22.4 L at STP) 11. ゴog Na × mol -1.78 mol n, 50.0 g of nitrogen (N2) has a volume of-一liters at STP. 18 met I mo V= 39.9 L 12. 1.00 x 10 g of oxygen (O2) is added to the gas in Question 11. What is the volume of the combined gases at STP? 13· What is the density of carbon dioxide at STP in grams per liter?

Answer 1

m = 50.0 g n = 50.0 g times 1 mol/28.0134 g = 1.78486 mol 1 mol = 22.4L V = x mol times 22.4L/1 mol V = 1.78486 mol times 22.4L/1mol V = 40.0L m = 1.00 times 10^2 g = 100.0g n = 100.0g times 1 mol/31.9988 g = 3.12512 mol 1 mol = 22.4L V = x mol times 22.4L/1 mol V = 3.12512 mol times 22.4L/1 mol V = 70.0L V_Total = V_n + V_o V_Total = 40.0L + 70.0L V_Total = 110.0L D = MP/RT D = 44.01 mol^-1 times 1.00 atm/0.0820587L atm mol^-1 K^-1 times 273.15K D = 1.96 g/L or D = M/22.4L D = 44.01g/22.4L D = 1.96 g/L