If the Ka of a monoprotic weak acid is 2.4 x 10-6, what is the pH...

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If the Ka of a monoprotic weak acid is 2.4 x 10-6, what is the pH of a 0.45 M solution of this acid? pH =

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Answer 1

Answer #1

HA > H+ + A 0.45M c - x + E 0.45-x Ka = [H+] (A) [HA] 2.4x10-6- X X 0.45-X x2 +2.4x10bx - 2.4x16x 0.45=0 x=0.001039m [HT] =

Answer 2

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