Question

A kidnapper demands a 44.0-kg cube of gold as a ransom. The density of gold is 19.3×103kg/m3.

Answer 1

$density = \frac{mass}{volume}$

$19.3\times 10^{3} = \frac{44}{volume}$

$volume = \frac{44}{19.3\times 10^{3}} = 2.279\times 10^{-3} m^{3}$

$volume = a^{3}$

$a^{3} = 2.279\times 10^{-3}$

$a = 0.1332m$