Question

Exercise 6. The graph of a function f(x) is given. Using the geometry of the graph, evaluate the definite integrals. - 1 2 3 4 51 $*(dx los pcdx S'f(x)dx les srcade (o) f(x)dx 19 P-2f(x)dx

Answer 1

* Answers faridx=5623.doc (** f(R)=-2 in [0,23 = -24 dec = -2 [x] - 3-2[2-0] = -2[2] =-4 I foo do Sfodd x + ² fox) dx - To find fonda . I fox) dx =((2x-6) dx ( \ Equation of straight line points (2,-2) and (3,0) is passing through the (4+2)=(0-(-2)(x-2) i f120= 2X6 in > y= 2x-6 [273] I fouldze - Tar (2x-6) dec = 5 2x dx - § 6 de

عمر كحولي 2=-- = z[1] = 6 [2] - [ 9 - 427-6(3-2) =25] =6(1) = 5 - 6 = f40d2C í fx) dx = - 4 - - - I fx) dx = -5 dx - f fol dx + (fox)dx - To find foldx f foo dx = foc-3dxo 3 Equation of straight line passing points (3,0) and (5,2) is (y-1 ( through the

(3يات ( روعي ( = ع و رفع ملودرد (كه ن و (6-3) dx (fo) dx = 9 _ 8 پا سوله و ک ی ۔ / / - کو۔ = =ق= [ع]3 | I fx)dx=2 می دهد

Date: @ fccdx = {fondct s fonda - 3-+2 Sfondx = 11 no طام - -ffc dx = -2 fo) dx = -2 dx = -2 S foodx 5-26-5) = 10 owl -2 fQody sle -