4. At a given temperature, K = 1.44 × 10-2 for the reaction: N2(g) + 3H2(g)...
4. At a given temperature, K = 1.44 × 10-2 for the reaction:
N2(g) + 3H2(g) ⇌ 2NH3(g) Calculate values of K for the following reactions at the given temperature.
a. 4NH3(g) ⇌ 2N2(g) + 6H2(g)
b. ½N2(g) + ³∕2H2(g) ⇌ NH3(g)
Homework Answers
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4. At a given temperature, K = 1.44 × 10-2 for the reaction:
N2(g) + 3H2(g)...
2. At 55°C, the equilibrium constant for the reaction N2(g) + 3H2(g) + 2NH3(g) is Kp=0.05....
2. At 55°C, the equilibrium constant for the reaction N2(g) + 3H2(g) + 2NH3(g) is Kp=0.05. What is the equilibrium constants Kc and Kp for the reaction 4NH3 + 2N2(g) + 6H2(g)? Kp = 400 Kc = 7.62 x 10 3. For the reaction given below, 10.00 moles of A and 25.00 moles of B are placed in a 5.00-L container at 120 °C. A(g) +2B(g) → C(g) At equilibrium, the concentration of A is 0.5 mol/L. What is the...
Given the following data for heats of reaction N2(g) + 3H2(g) ----> 2NH3(g) H = -91.8 kJ...
Given the following data for heats of reaction
N2(g) + 3H2(g) ---->
2NH3(g) H
= -91.8 kJ
C(graphite) + 2H2(g) ------->
CH4(g)H
= -74.9kJ
H2(g) + 2C(graphite) + N2(g)
--------> 2HCN(g) H
= 270.3 kJ
Calculate
H for the reaction used to make HCN
CH4(g) + NH3(g) --------> HCN(g) +
3H2(g)
The ΔHΔH for the reaction N2(g)+3H2(g)N2(g)+3H2(g) →→ 2NH3(g)2NH3(g) is −123.77kJmol−1−123.77kJmol−1 at 1000 K. The heat capacities...
The ΔHΔH for the reaction N2(g)+3H2(g)N2(g)+3H2(g) →→ 2NH3(g)2NH3(g) is −123.77kJmol−1−123.77kJmol−1 at 1000 K. The heat capacities of the reactants and products are CP,m=CP,m= 3.502 RR, 3.466 RR, and 4.217 RR for N2(g)N2(g), H2(g)H2(g), and NH3(g)NH3(g), respectively. Calculate ΔHfΔHf of NH3(g)NH3(g) at 500 KK from this information. Assume that the heat capacities are independent of temperature. Express your answer to four significant figures and include the appropriate units.
Question The equilibrium constant, Kc, for the following reaction is 3.72 at 701 K. 2NH3(gN2(g) +...
Question The equilibrium constant, Kc, for the following reaction is 3.72 at 701 K. 2NH3(gN2(g) + 3H2(g) Calculate Kc at this temperature for the following reaction: 1/2N2(g) +3/2H2(g) NH3( Kc
∆Sₒ is -198.2 J/K for the reaction N2(g) + 3H2(g) --------à 2NH3(g) at 25C®. Given Sₒ(N2)=191.5...
∆Sₒ is -198.2 J/K for the reaction N2(g) + 3H2(g) --------à 2NH3(g) at 25C®. Given Sₒ(N2)=191.5 J/K-mol, and Sₒ(H2)=130.58 J/K-mol, what is Sₒ(NH3)? ( 4 points)
A student ran the following reaction in the laboratory at 698 K: N2(g) + 3H2(g) 2NH3(g)...
A student ran the following reaction in the laboratory at 698 K: N2(g) + 3H2(g) 2NH3(g) When she introduced 3.37×10-2 moles of N2(g) and 7.09×10-2 moles of H2(g) into a 1.00 liter container, she found the equilibrium concentration of NH3(g) to be 1.74×10-3 M. Calculate the equilibrium constant, Kc, she obtained for this reaction. Kc =
A student ran the following reaction in the laboratory at 745 K: N2(g) + 3H2(g) 2NH3(g)...
A student ran the following reaction in the laboratory at 745 K: N2(g) + 3H2(g) 2NH3(g) When she introduced 3.44x10-2 moles of N2(g) and 5.80x10-2 moles of H2(g) into a 1.00 liter container, she found the equilibrium concentration of NH3(g) to be 7.82x10-4M. Calculate the equilibrium constant, K., she obtained for this reaction. K=
Consider the following reaction where K = 0.159 at 723 K: N2(g) + 3H2(g) = 2NH3(g)...
Consider the following reaction where K = 0.159 at 723 K: N2(g) + 3H2(g) = 2NH3(g) A reaction mixture was found to contain 4.65*10*2 moles of N2(g), 3.76x10-2 moles of H2(g) and 5.50*10-4 moles of NH3(g), in a 1.00 Liter container Indicate Truc (T) or False (E) for each of the followingi 1. In order to reach equilibrium NH3(g) must be consumed. 2. In order to reach equilibrium K must decrease. 3. In order to reach equilibrium N, must be...
The equilibrium constant, Kc, for the following reaction is 1.31×10-2 at 700 K. NH4I(s) (forward/reverse arrow)NH3(g)...
The equilibrium constant, Kc, for the following reaction is 1.31×10-2 at 700 K. NH4I(s) (forward/reverse arrow)NH3(g) + HI(g) 1. Calculate Kc at this temperature for the following reaction: NH3(g) + HI(g) (forward/reverse arrow)NH4I(s) Kc = 2. The equilibrium constant, Kc, for the following reaction is 2.03 at 677 K. 2NH3(g) (forward/reverse arrow)N2(g) + 3H2(g) Calculate Kc at this temperature for: N2(g) + 3H2(g) (forward/reverse arrow)2NH3(g) Kc =
For the reaction N2(g)+3H2(g)⇌2NH3(g) Kp = 3.50×10−3 at 262 ∘C . What is K for the...
For the reaction N2(g)+3H2(g)⇌2NH3(g) Kp = 3.50×10−3 at 262 ∘C . What is K for the reaction at this temperature?
2. At 55°C, the equilibrium constant for the reaction N2(g) + 3H2(g) + 2NH3(g) is Kp=0.05. What is the equilibrium constants Kc and Kp for the reaction 4NH3 + 2N2(g) + 6H2(g)? Kp = 400 Kc = 7.62 x 10 3. For the reaction given below, 10.00 moles of A and 25.00 moles of B are placed in a 5.00-L container at 120 °C. A(g) +2B(g) → C(g) At equilibrium, the concentration of A is 0.5 mol/L. What is the...
Given the following data for heats of reaction
N2(g) + 3H2(g) ---->
2NH3(g) H
= -91.8 kJ
C(graphite) + 2H2(g) ------->
CH4(g)H
= -74.9kJ
H2(g) + 2C(graphite) + N2(g)
--------> 2HCN(g) H
= 270.3 kJ
Calculate
H for the reaction used to make HCN
CH4(g) + NH3(g) --------> HCN(g) +
3H2(g)
Question The equilibrium constant, Kc, for the following reaction is 3.72 at 701 K. 2NH3(gN2(g) + 3H2(g) Calculate Kc at this temperature for the following reaction: 1/2N2(g) +3/2H2(g) NH3( Kc
A student ran the following reaction in the laboratory at 745 K: N2(g) + 3H2(g) 2NH3(g) When she introduced 3.44x10-2 moles of N2(g) and 5.80x10-2 moles of H2(g) into a 1.00 liter container, she found the equilibrium concentration of NH3(g) to be 7.82x10-4M. Calculate the equilibrium constant, K., she obtained for this reaction. K=
Consider the following reaction where K = 0.159 at 723 K: N2(g) + 3H2(g) = 2NH3(g) A reaction mixture was found to contain 4.65*10*2 moles of N2(g), 3.76x10-2 moles of H2(g) and 5.50*10-4 moles of NH3(g), in a 1.00 Liter container Indicate Truc (T) or False (E) for each of the followingi 1. In order to reach equilibrium NH3(g) must be consumed. 2. In order to reach equilibrium K must decrease. 3. In order to reach equilibrium N, must be...
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