Two slits spaced 0.130 mm apart are placed 90.0 cm from a screen and illuminated by coherent light with wave length 550 nm. the intensity at the center of the central maximum ( degrees) is 4.00 X 10^{-6} W/m^{2} A) what is the distance on the screen from the center of the central maximum to the first minimum? B) what is the intenisty at a point midway between the center of the central maximum and the first minimum?
Two slits spaced (2d) = 0.130 mm =0.130*10^{-3}m
The distance between the slits and screen is (D) = 90.0 cm =0.9m
The illuminated by coherent light with wave length (lamda) = 550 nm =550*10^{-9}m.
The intensity at the center of the central maximum ( degrees) is (I) =4.00 X 10^{-6} W/m^{2}
For a first dark fringe i.e fo the first minima
xn =(D/2d)(2n+1)lamda/2 for firstminima n=1
now the distance on the screen from the center of the central maximum to the first minimum
xn =(D/2d)*(2n+1)lamda/2 =(0.9/0.130*10^{-3}m)(3)*550*10^{-9}m/2 =571.15*10^{-6} =5.711mm
At the mid point means
xn =2.855mm
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