if
A = 0.334
then
A = 2417.5*C + 0.0483
0.334= 2417.5*C + 0.0483
solve for C
C = (0.334-0.0483)/2417.5
C = 0.000118 M
[FeSCN+2] = 0.000118 M
Q4
Kf = [FeSCN+2]/[Fe+3][SCN-]
initially
[Fe+3] = M1V1/(Vtotal) = 0.002*3/(3+2+5) = 0.0006
[SCN-] = M1V1/(Vtotal) = 0.002*2/(3+2+5) = 0.0004
[FeSCN+2] = 0
in equilbirium
[Fe+3] = = 0.0006-x
[SCN-] = = 0.0004 - x
[FeSCN+2] = x
get x
A = 2417.5*C + 0.0483
0.118 = 2417.5*C + 0.0483
C =( 0.118 -0.0483)/2417.5 = 0.0000288 M
[Fe+3] = = 0.0006-0.0000288 = 0.0005712
[SCN-] = = 0.0004 - 0.0000288 = 0.0003712
[FeSCN+2] = 0.0000288
substitute in Kf
Kf = (0.0000288 )/(0.0003712*0.0005712 )
Kf = 135.83
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