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The charge is not in contact with hollow conductor , hence
Qinside = 0
Qoutside = 0
due to negative charge on the hanging charge, an equal amount of positive charge is induced on he inner surface of the conductor. So
Qinside = 2.9 C
and equal amount of negative charge goes away to the surface to keep the hollow conductor neutral.
Qoutside = - 2.9 C
Due to transfer of charge, all the charge goes to the surface of hollow conductor, hence
Qinside = 0 C
Qoutside = - 2.9 C
The charge remains undisturbed on the surface of conductor, hence
Qinside = 0 C
Qoutside = - 2.9 C
1. - 18 points SerCP11 15..P.039. My Notes Ask Your Teache Refer to the figure below....
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