Question

4) All signals in the 'H NMR below correspond to particular hydrogens in the molecule. Assign the NMR spectrum by labeling each proton in the molecule with the appropriate lettered signal. OMe 3H, S HO 3H, S 4H, m 1H, s 1H, br PPM 6H, d 3H, d 2H, S 3H, m 1H, q1H, sept PPM

Answer 1

A. 1H, bsoad stnglet at Roppm is because bead peelt and highly deshield becouse of 13. 4H ,n A. oMe es bsoad oton which giv 4H, meltiplet is because of azomatic psoton tesonana, ing7,0-7,4 Ppm which ร.gion C IH , singlet 8 5.9 ppm. อ. 3Hzse s natong as singlet at 83.9 ppm is becouse of olfinic prsobn zesonaledat due to 0-0 O-C Psoton E.зи zes o nati n 9 as singlet atg8e.3 ppm 's due to-CH3 Singlet at R.3 ppm is due to -CH 3 4H, m 0 7. R-.G ppm is due to asomatic Deshielded proton ซesonating at f 5.4 ppm RSS berouse of ding CHPooton

CH ngpsołon 11, seplet beof CH attached to asomatio g ao omatic and sevksounded by tooCHa gooup a 6R.8 ppm 1 . 5 ppm) , doublet because of -CH poet。 0 18 ppm, doublet because f gooup n -CH 0%-> E, 34, d H → 11-1 CA) 3 1H, Sepl omatic poołor