Question

i got 1.49 kN/m but it as wrong

Determime the maximum allowable intensity w of the distributed load that can be applied to BC (which is infinitely rigid) that will not allow AB to buckle. Express your answer in kN/m. For potential buckling about x-x, use pin connections at A and B. For potential buckling about y-y, use fixed connections at A and B. Use a Factor of Safety of 4, and a modulus of 180 GPa for AB. a = 21 mm b= 28 mm L = 2.2 m W ВП — 1.5 m - 0.5 m

Answer 1

- Dorow a foee body diagram. -2.1 b.28 m Factors of Factor of safety :4 sarem 24 E 180 Gpe. Fax porentiaj buckling abow seae, use pin connection at a and B. moment of inertia about ze.se Ixx Iba 462873621) ba: (2873621) _IRX2_38416mmy Buckling Load__for Both end_pinned effective length_Leo L 2.2 m) : 2200 mm Buckling_Lood_ P . : 726 te

Pc: 72 (180x103) x 38416 22002 - 14100 N .. 14.1 kr sole Load pga den 1411. 3.525 kr FOS - 1.5 m 0.5 0.5 CITTTTTTTTTTTTT Rc Now RB Rg: pgr. 3.525 kr. Taking moment about c. - C+ Emzo wa)(1)-ROCIS)=0 w occue AS (5) 3.Sas X 2 2.64375 knym.. 2 For polential buckling about 4-4 use fixed connection at A and B. moment of inertia about 4.4 Jis bai: 2(28) (2113: 2150g mmy -

Buckiing Load foro Botteng_fixed effective length Le: L2 2200, 1100mm - Pas R : 1:26r Lez 772 x 180X163 x 21609 11002 31726 NY B: 276 ka Bl: 275 sare' load psipe FOR - :7.819 kry. foom equarion © 662)(1)- 7.819 (1:5)= 0 W : 5.864 kn)