Question

2TX 2TX 27 27 9 - 18. 27x* = 81x 27X -81XO 27x0 X-3- --ix -37x 27(x-3) = X 10. What type of solutions does the following equation have? Do not solve the equation 3x +10x - 40 62-42C - Y TOD 48 3702-400 F 149 20. - *. = 2 + 12. 3x(x-4)=2x-y + 3x2-76 =24 3x2-12 = 2 X -8+2 " 3x² - 12 = 2x + 4 Part III : Answer each of the following questions X+30 X330 x 2 + 20 x2-8 21. Solve for x. (x29x2 +9) 19-9 -1942 x-x - 72 =0 (x+3)(x-3)C X +S). X²F8 Fizite 3y 4) - 2 CX-1) +12 ( 4) 3x - 3 -3 6 CX -3 CX 2 22. Write an equation that has following solutions. 2 and -2 X-2 X - - 33 x² - 4x -4 -2 0 :: 3x² - 4x-4=0 (x-2)(x+ ) 3(x2)-4(1)-403) = 0 SOLUTION ser 23. Solve the system by the substitution method. X = 30 Yet 3D y_3=0 9x² + 2(3x)² = 90 9x2 + 2y2 = 90 9x?+18XP-90 y - 3x y 3 28x220 3x3x 24. In a right triangle, one leg of this triangle represents a distance of is 12 miles. The other leg of the triangle is 6 miles shorter than the hypotenuse. What are the lengths of the three sides?

need help with 24.

Answer 1

Solution- Given- A Right Angle triangle, Length = 12 miles Hypotenuse = x Length of the third fide = %-6 (Given) Figure - X-6 H 12 miles using Pythagoras Theorem - CHypotenuse )? (Bases ? + (perpendicular 2 12° +(-6) ? ☺ #2 = 144 + 4+36-12 3) 12x = 180 x= 15 miles x-6= 9 miles The length of the three sides are 9 miles, 12 miles and 15 miles Aus Scanned with CamScanner