Question

STEP BY STEP SOLUTION PLEASE!!

1. What is the equivalent resistance of the above circuit? 2. If the emf of the battery is 10V, what current is leaving the battery? 3. Is the current flowing in a generally clockwise or counterclockwise direction? (Mind the definition of current)

Answer 1

Here ,

for the R8 and R10 in series

R11 = 10 + 2 = 12 ohm

for R11 in parallel to R9

R12 = 12 * 6/(12 + 6)

R12 = 4 Ohm

for R12 and R4 in series

R13 = 4 + 8

R13 = 12 Ohm

for R13 and R6 in parallel

R14 = 12 * 8/(12 + 8)

R14 = 4.8 Ohm

for R5 and R14 in series

R15 = 4.8 + 4

R15 = 8.4 Ohm

for R4 and R15 in parallel

R16 = 8.4 * 8/(8.4 + 8)

R16 = 4.1 Ohm

for R3 and R16 in series

R17 = 4 + 4.1 = 8.1 Ohm

for R17 and R2 in parallel

R18 = 8.1 * 8/(8.1 + 8)

R18 = 4.025 Ohm

for R1 and R18 in series

Req = 4.025 + 6

Req = 10.025 Ohm

tge equivalent resistance of the circuit is 10.025 Ohm

2)

current in battery = V/Req

current in battery = 10/10.025

current in battery = 1 A

3)

the current is flowing from the positive terminal of battery

hence it is clockwise