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For a recent 10k run, the finishers are normally distributed with mean 58 minutes and standard...


For a recent 10k run, the finishers are normally distributed with mean 58 minutes and standard deviation 9 minutes Click here
For a recent 10k run, the finishers are normally distributed with mean 58 minutes and standard deviation 9 minutes Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. Jack was told his race time placed him in the 35th percentile for the finishing times. What was his finishing time? w The 35th percentile is minutes (Round to two decimal places as needed.) en Ta SI DI
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9 M=58,6=9 P(x2x)=0-35 =) para entre 15953) 20:35 X-58 70.352-0.385 [using z table n o 5) X-58-0.385x9 = 54.535 z = 54.54 Ans

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