Homework Answers
[NH3] = 0.9M
[NH4Cl] = 0.3M
PKb = -logKb
= -log1.8*10^-5
= 4.74
POH = Pkb + log[NH4Cl]/[NH3]
= 4.75 + log0.3/0.9
= 4.75-0.477
= 4.273
PH = 14-POH
= 14-4.273
= 9.73
9.73 >>>>>answer
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