Homework Answers
| Customer # | Arrival time | Service time | Waiting time | Time in system | Idle time | Interarrival time |
| 1 | 0 | 4 | 0 | 4 | 0 | |
| 2 | 8 | 1 | 0 | 1 | 4 | 8 |
| 3 | 14 | 4 | 0 | 4 | 5 | 6 |
| 4 | 15 | 3 | 3 | 6 | 0 | 1 |
| 5 | 23 | 2 | 0 | 2 | 2 | 8 |
| 6 | 26 | 4 | 0 | 4 | 1 | 3 |
| 7 | 34 | 5 | 0 | 5 | 4 | 8 |
| 8 | 41 | 4 | 0 | 4 | 2 | 7 |
| 9 | 43 | 5 | 2 | 7 | 0 | 2 |
| 10 | 46 | 3 | 4 | 7 | 0 | 3 |
| Average | 3.5 | 0.9 | 4.4 | 1.8 | 5.11 |
(i) Average waiting time = 0.90 minutes
(ii) Prob(customers waiting) = 3/10 = 30%
(iii) Prob(idle server) = total idle time / total run time = (1.8*10) / 46 = 0.39
(iv) Average service time = 3.5 minutes
(v) Average time between arrivals = 5.11 minutes
(v) Average time in the system = 4.4 minutes
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