A 98% confidence interval for a population proportion is given as 0.531 < p < 0.693. Round your answers to 3 decimal places.
(a) Calculate the sample proportion.
p̂ =
(b) Calculate the margin of error.
E =


A 98% confidence interval for a population proportion is given as 0.531 < p < 0.693....
Use the normal distribution to find a confidence interval for a proportion p given the relevant sample results. Give the best point estimate for p , the margin of error, and the confidence interval. Assume the results come from a random sample. A 95% confidence interval for the proportion of the population in Category A given that 18% of a sample of 450 are in Category A. Round your answer for the point estimate to two decimal places, and your...
a.) Use the normal distribution to find a confidence interval for a proportion p given the relevant sample results. Give the best point estimate for p, the margin of error, and the confidence interval. Assume the results come from a random sample. Answer all parts please, not just the confidence interval. A 95% confidence interval for p given that p-hat=0.75 and n=100. Round your answer for the point estimate to two decimal places, and your answers for the margin of...
A 98% confidence interval for a population mean is given as 31.4 < μ < 40.8. Round your answers to 1 decimal place. (a) Calculate the sample mean. x = (b) Calculate the margin of error.
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Use the normal distribution to find a confidence interval for a proportion p given the relevant sample results. Give the best point estimate for p, the margin of error, and the confidence interval. Assume the results come from a random sample. A 90% confidence interval for p given that p^=0.41 and n=475. Round your answer for the best point estimate to two decimal places, and your answers for the margin of error and the confidence interval to three decimal places...
Use the normal distribution to find a confidence interval for a proportion p given the relevant sample results. Give the best point estimate for p, the margin of error, and the confidence interval. Assume the results come from a random sample. A 99% confidence interval for p given that p = 0.7 and n = 100. Round your answer for the point estimate to two decimal places, and your answers for the margin of error and the confidence interval to...
Use the normal distribution to find a confidence interval for a proportion p given the relevant sample results. Give the best point estimate for p, the margin of error, and the confidence interval. Assume the results come from a random sample. A 90% confidence interval for p given that p^=0.33 and n=475 . Round your answer for the best point estimate to two decimal places, and your answers for the margin of error and the confidence interval to three decimal...
Use the normal distribution to find a confidence interval for a proportion p given the relevant sample results. Give the best point estimate for p, the margin of error, and the confidence interval. Assume the results come from a random sample. A 99% confidence interval for p given that p^=0.75 and n=140. Round your answer for the point estimate to two decimal places, and your answers for the margin of error and the confidence interval to three decimal places. Point...
Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p. Round to three decimal palces Of 98 adults selected random from one town, 68 have health insurance Find a 90% confidence interval adults in he own who have heal e proportion on r e a ns rance 0585 < p < 0 802 B. 0.617<p<0.770 A. C. 0603 p<0.785 D. 0.574p<0.814
Use the given degree of confidence and sample data to...
Use the normal distribution to find a confidence interval for a proportion p given the relevant sample results. Give the best point estimate for p, the margin of error, and the confidence interval. Assume the results come from a random sample. A 95% confidence interval for p given that p^=0.39 and n=525. Round your answer for the best point estimate to two decimal places, and your answers for the margin of error and the confidence interval to three decimal places....