Question

In an experiment in breeding mice, a geneticist has obtained 120 brown mice with pink eyes, 48 brown mice with brown eyes, 36
Make sure to use R

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Answer #1

Sol:

expected percentages are

9/9+3+3+1=9/16=0.5625

3/16=0.1875

3/16=0.1875

1/16= 0.0625

Solution-1:

Ho:fo=fe

observed frequencies and expected frequencies are same

Ha: fo not =fe

observed frequencies differs from expected frequencies

Solution-2:

Rcode:

observedeyes <- c(120,48,36,13)
expectedeyes <- c(0.5625,0.1875,0.1875,0.0625)
chisq.test(observedeyes, p=expectedeyes)

Output:

Chi-squared test for given probabilities

data: observedeyes
X-squared = 1.9124, df = 3, p-value = 0.5908

p value= 0.5908

Solution-3:

p value= 0.5908

p>0.05

Do not reject Ho

Accept Ho

Conclusion:

There is sufficient evidence at 5% level of significance to conclude that data is compatible with the theory

as obseved frequencies are same as expected frequencies

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