Sol:
expected percentages are
9/9+3+3+1=9/16=0.5625
3/16=0.1875
3/16=0.1875
1/16= 0.0625
Solution-1:
Ho:fo=fe
observed frequencies and expected frequencies are same
Ha: fo not =fe
observed frequencies differs from expected frequencies
Solution-2:
Rcode:
observedeyes <- c(120,48,36,13)
expectedeyes <- c(0.5625,0.1875,0.1875,0.0625)
chisq.test(observedeyes, p=expectedeyes)
Output:
Chi-squared test for given probabilities
data: observedeyes
X-squared = 1.9124, df = 3, p-value = 0.5908
p value= 0.5908
Solution-3:
p value= 0.5908
p>0.05
Do not reject Ho
Accept Ho
Conclusion:
There is sufficient evidence at 5% level of significance to conclude that data is compatible with the theory
as obseved frequencies are same as expected frequencies
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