Category | Observed Frequency (O) | Proportion, p | Expected Frequency (E) | (O-E)2/E |
0-24 | 31 | 0.25 | 100 * 0.25 = 25 | (31 - 25)2/25 = 1.44 |
25-49 | 20 | 0.25 | 100 * 0.25 = 25 | (20 - 25)2/25 = 1 |
50-74 | 29 | 0.25 | 100 * 0.25 = 25 | (29 - 25)2/25 = 0.64 |
75-99 | 20 | 0.25 | 100 * 0.25 = 25 | (20 - 25)2/25 = 1 |
Total | 100 | 1.00 | 100 | 4.0800 |
Test statistic:
χ2 = ∑ ((O-E)2/E) = 4.08
df = n-1 = 3
Critical value:
χ2α = CHISQ.INV.RT(0.05, 3) = 7.815
Do not reject the null hypothesis. there is not sufficient evidence to warrant rejection of the claim.
The result does not support.
Conduct the hypothesis test and provide the test statistic and the critical value and state the...
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You are conducting a multinomial hypothesis test (αα = 0.05) for
the claim that all 5 categories are equally likely to be
selected.
Category
Observed
Frequency
A
20
B
15
C
15
D
12
E
18
What is the chi-square test-statistic for this data?
χ2=χ2=
What are the degrees of freedom for this test?
d.f. =
What is the p-value for this sample? (Report answer accurate to
four decimal places.)
p-value =
The p-value is...
less than (or equal to)...
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ice with Conduct the hypothesis test and provide the test statistic and the critical value, and state the conclusion. A person drilled a hole in a die and filled it with a lead weight, then proceeded to roll it 200 times. Here are the observed frequencies for the outcomes of 1, 2, 3, 4, 5, and 6, respectively: 30, 32, 44, 39, 28, 27. Use a 0.025 significance level to test the claim that the...
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