Question

Problem 1 What is an angle 0 in radians such that 0 3 0 < 2x that occupies the same spot on the circle as -960°? Problem 2 If I alter the function sin to get the function cos, what values of a, b, c, and d give me the equality cos (0) asin(60 + c) + d? Problem 3 Give me all values of 0 such that cos (0) 0.

Answer 1

Problem 1

Every spot x° on circle is occupied by x°+2nπ, where n is a integer.

The spot -960°=-1080+120

So will be occupied by 120°. So in Radians it will be $\frac{2 \pi }{3}$ .

Problem 2

$Cos\theta$ can be obtained from $Sin\theta$ by shifting it $\frac{\pi}{2}$ units left.

So $Cos\theta =sin(\theta +\frac{\pi}{2})$

So a=b=1, c=d=0

Problem 3

$Cos\theta =0$ if $\theta =\frac{(2n+1)\pi}{2}$