(i) the volume of sodium hydroxide taken = 2mL = V1 concentration = 4M = M1
final volume = V2 = 100mL concentration = M2
Therefore
M1V1 = M2V2
M2 = 2 X 4 / 100= 0.08 M
2) the volume of sodium hydroxide taken = 4mL = V1 concentration = 4M = M1
final volume = V2 = 100mL concentration = M2
Therefore
M1V1 = M2V2
M2 = 4 X 4 / 100= 0.16 M
3) the volume of sodium hydroxide taken = 6mL = V1 concentration = 4M = M1
final volume = V2 = 100mL concentration = M2
Therefore
M1V1 = M2V2
M2 = 6 X 4 / 100= 0.24 M
4) the volume of sodium hydroxide taken = 8mL = V1 concentration = 4M = M1
final volume = V2 = 100mL concentration = M2
Therefore
M1V1 = M2V2
M2 = 8 X 4 / 100= 0.32 M
5) the volume of sodium hydroxide taken = 10mL = V1 concentration = 4M = M1
final volume = V2 = 100mL concentration = M2
Therefore
M1V1 = M2V2
M2 = 10 X 4 / 100= 0.4 M
Use a volumetric pipet to deliver 2 mL of 4 M sodium hydroxide solution to each...
A pipet is used to transfer 10.00 mL of a 4.00 M stock solution in flask “S” to a 25.00-mL volumetric flask “A,” which is then diluted with DI H2O to the calibration mark. The solution is thoroughly mixed. Next, 1.00 mL of the solution in volumetric flask “A” is transferred by pipet to a 50.00-mL volumetric flask “B” and then diluted with DI H2O to the calibration mark. Calculate the molarity of the solution in volumetric flask “B.”
Concentration of NaOH = 1600 x10- Molar Sodium hydroxide Nach Trial 1 Trial 2 Trial Trial 4 2.60/1.20 11.40/1.30 28.20 29.10.26.1026.50 Initial buret reading Final buret reading Volume of NaOH added Moles of NaOH added Moles of HCl reacted Molarity of diluted HCI Molarity of undiluted HCI Average molarity of undiluted HCI Precision PROCEDURE 1. Obtain approximately 40 mL of an unknown acid in an Erlenmeyer flask from your teaching assistant. 2. Clean your 250-ml volumetric flask (contains exactly 250.00...
Concentration of NaOH = 1600 x10- Molar Sodium hydroxide Nach Trial 1 Trial 2 Trial Trial 4 2.60/1.20 1.40/1.30 28.20 29.10.26.1026.50 Volume of NaOH added Initial buret reading Final buret reading Moles of NaOH added Moles of HCl reacted Molarity of diluted HCI Molarity of undiluted HCI Average molarity of undiluted HCI Precision PROCEDURE 1. Obtain approximately 40 mL of an unknown acid in an Erlenmeyer flask from your teaching assistant. 2. Clean your 250-ml volumetric flask (contains exactly 250.00...
A chemist must prepare 750.0 mL of sodium hydroxide solution with a pH of 13.70 at 25 °C. She will do this in three steps: • Fill a 750.0 mL volumetric flask about halfway with distilled water. • Weigh out a small amount of solid sodium hydroxide and add it to the flask. • Fill the flask to the mark with distilled water. Calculate the mass of sodium hydroxide that the chemist must weigh out in the second step. Round...
What piece of glassware would a student use to deliver 4.00mL of solution? A. 25 mL volumetric flask B. 10 mL beaker C. 5mL Erlenmeyer flask D. 25mL graduated cylinder E. 10mL volumetric pipet
Question:
Prelab Question #2: A student has weighed out 850 mg of 1-pentanol in 50 mL volumetric flask and prepared four standard solutions as described in this procedure. Calculate concentrations of 1-pentanol in mg/mL in each of these solutions. Instructional Videos to Watch before Lab Fundamentals of GC EXPERIMENTAL PROCEDURE Preparation of Solutions. Get a glassware bin from your TA. Rinse five 10 .00 mL volumetric flasks with 2-propanol (isoproponal) to remove any al cohols remaining in the nprevious usage....
Please explain in detail You are going to standardize a 0.80% solution of sodium hydroxide solution for which the molarity is approx 0.20M. You will have dry succinic acid (H2C4H4O4) , a 250 mL volumetric flask, a 25.00mL pipet, a 50.00mL buret, a phenolphthalein indicator solution, and other standard lab equipment. For each titration you will withdraw a 25.00mL sample of the succinic acid solution with a volumetric pipet. Therefore you will deliver exactly one-tenth of your initial mass of...
Calculate the initial concentration of iron(III) in
solution #1, #2, #3.
Beaker (mL) Table 1. Reagent Solutions Provided by the Stockroom Solution Name Reagent [Reagent] (M) Volume (mL) Standard iron Fe(NO3)3 2.50 x 10 in 0.10 M HNO3 nitric acid HNO3 0.10 120 35 50 250 conc. SCN KSCN 0.50 30 50 dilute SCN KSCN 2.50 x 10-3 30 50 Worksheet 1 #1 5.00 #2 10.00 #3 15.00 Dilute iron (mL) [Fe**] (M) [Fe(SCN)?*] (M) %T 480 58.9 35.8 21.5...
Question 1 2 pts 3.34 mL of an unknown glucose solution was diluted in a 100.00 mL of volumetric flask with distilled water. 10mL of that solution and 4.00 mL of the ferricyanide reagent was placed in a second 100.00 mL volumetric flask and diluted to the mark with distilled water. Spectrophotometric analysis of the glucose/ferricyanide solution showed that the concentration of glucose was 0.070 M. What is the concentration of glucose in the unknown solution?
Question 1 2 pts 3.34 mL of an unknown glucose solution was diluted in a 100.00 mL of volumetric flask with distilled water. 10mL of that solution and 4.00 mL of the ferricyanide reagent was placed in a second 100.00 mL volumetric flask and diluted to the mark with distilled water. Spectrophotometric analysis of the glucose/ferricyanide solution showed that the concentration of glucose was 0.070 M. What is the concentration of glucose in the unknown solution?