Q12. Given : pH = 3.84
Autoionization constant of water, Kw = 1.0 x 10-14
pKw = -log(Kw)
pKw = -log(1.0 x 10-14)
pKw = 14
pOH = pKw - pH
pOH = 14 - 3.84
pOH = 10.16
show work Question 12 4/4 pts A solution has a pH value of 3.84. What is...
show work
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please show full work for understanding purposes:)
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a solution has a POH at 6.50 at 50° C what is the Ph of the
solution given that K=6.22 X 10-15
please explain HOW too
Use pOH in calculations Question A solution has a pOH of 6.50 at 50°C. What is the pH of the solution given that Kw 6.22 x 10-15 1 at this temperature? Round the answer to two decimal places. Provide your answer below: pH
. A solution has a pH value of 3.66. What is the pOH for this solution? a. 7.00 b. 3.83 c. 3.66 d. 2.19 e. 10.34
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