Question

3. What is the minimum amount of energy required for a 70.0-kg climber carrying a 20.0-kg Pack to climb Mt. Everest, which is 8850 m high?4. A bomb explodes on an asteroid and breaks it into two pieces. One of which is moving to left at 20 m/s and the other one is moving to the right at 40m/s What are the ratios of Kinetic Energy and the magnitude of Momentum of the two pieces?

Answer 1

$3.$  $E = \Delta U = mgh$

$E = (70+20) \times 9.8 \times 8850 = 7805.7kJ$

$4.$

$\frac{KE_1}{KE_2 } = \frac{m_1 v_1^2}{m_2v_2 ^2} = \frac{P_1 v_1 } {P_2v_2 } = \frac{P_1 }{2P_2}$

$P_1 = P_2$ By conservation of momnetum

$\frac{KE_1}{KE_2} = \frac{1}{2}$

$\frac{P_1}{P_2} = \frac{1}{1}$