Question

The American Veterinary Association claims that the annual cost of medical care for dogs averages $110 with a standard deviation of $35. The cost for cats averages $125 with a standard deviation of $42. Some basic algebraic and statistical steps shows us that the average of the difference in the cost of medical care for dogs and cats is then $110-$125 = -$15. The standard deviation of that same difference equals $53. If the difference in costs follows a normal distribution, what is the probability that the cost for someone's dog is higher than for the cat?

A) 0.2830, B) 0.6103, C) 0.3897, D) 0.7170

Answer 1