Question

Top secret crates used for shipping computers are released down an incline at point A with a speed of 1 m/s that is set at an angle of 39º. The crates slide down the ramp with frictional value * = 0.25 onto a conveyor belt that moves at a rate of 3.1 m's. If the length of AB is 6 meters and BC is 6 meters, find the distance that the package will slide on the conveyor before coming to a stop. 2. A o 3.1m's I. XOXOXOXOXO 39 B+ 6m C 25 m (put units in the second box)

Answer 1

The solution for finding the distance that package will slide on the conveyor before coming to stop is given below as image file. Please rate the answer and revert me for any clarification in the solution.

Viony = 3.imis. N A Wazimis Mx 20-25 S 3 ms. 6m10=-390. 6m dan ban Free body diagram - INAB 00 ............ sy 90.4.399 51 nales 34 239 (fiction) FAB to.ro imgsinggo Efy 0 mg. we consider Nar-mg cos 39030 NAB = mgcos34 FAB = Hk NAB 0.25 mg cos 390 we know on suntace aty UAYB = mg ng Sin3qx (das) - FABX dan lupusg=_mgdab (sin 39*-0.25 6.5 39°) on Surface BC NBC- mga o NBC = mg dbe bmw FB.. - Hu X NBC = Mixx my ToByC = - tk mg o be mg. INDE

At point A Ken IxmxvAr CVA CVA = imis) "Now on to enagy 2 Point a Ċ XE dc Lom vc 2 equating Energy at point c. equal to from point A to Be B to c. (KEJA+UAAB+ UBAC = (KE)c. I my² + [mg dab (sin390 -0.25 cos 390 ] I mv + C-Hk mg db) multiply by a a divide by m. Na VART 2.89181x6 (Sin 390-0.25 Us 39 0.25 8.918.1X2 X 66.) (U) 029+2x9:51X.6.09.629.-0:23(0:727.). 29.43 Vea a 22.778 Ne 22.778 Vc = 4.77 3m ů Vbelt - 3.1mls. bany is the distance Package will slide on Conveyor before com coming - MXN N-mg o Ning iva ve? Mx Mg (x conv (z.conv) 63.1)? (84-77394. 2x0.25x9.8 (a conv) = a conv=2685m to stop Ex R. Fe - nung 2 . Ixgby Cycony) (3.1)? V? 2.MK 9