Homework Answers
P 0.05 atm
Kp = 3.9*10^-2
and
KP = PNH3*PH2S
since the other reactant is solid, it is not included
then
K = 3.9*10^-2
then
KP = PNH3*PH2S = 3.9*10^-2
in equilibrium
PNH3= PH2S
x^2 = 3.9*10^-2
x = sqrt(3.9*10^-2) = 0.1974841
PT = 0.1974841+0.1974841 =0.3949682
this is slightly favoured toward products
then, this is NOT in equilbirium
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For the reaction below at a certain temperature, it is found
that the equilibrium concentrations in a 5.05-L rigid container are
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M, and [HF] = 0.450 M.
H2(g) + F2(g) 2
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If 0.203 mol of F2 is added to this equilibrium
mixture, calculate the concentrations of all gases once equilibrium
is reestablished.
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