Answer 3:
As per the heat eqaution
Q = mc ΔT
m = mass of substance = 455 g
Q = heat required to reach the particular temperatrue
C= specific heat capcity of iron = 0.444 J/goC
ΔT = (Final Temperature -intial temperature) = (200-25 ) =175 oC
Q = 455 * 0.444 * 175
Q = 35353.5 J
Q = 35.35 Kj
So total heat required would be 35.35 KJ
Answer 4:
Part (i)
As compound is unionized so i value will be 1 in the below equaiton :
ΔT = Kb * m *i
Kb of water is 0.51c/m
ΔT = Boiling point of solution - boiling point of water
= 105.5 -100
= 5.5 oC
If we calculate the m for the same:
m = 5.5/0.51
= 10.784 mol/kg of water
As we have used the 250 g of water so mole of substance is = 10.784*0.25 = 2.696 moles.
As 12.5 g contains the 2.696 moles so 1 moles contains 4.63 g
so molar mass is 4.63 g/mole
3 2. According to the US Mint, a standard gold bar weighs in at 27.43 lb...
L. Explain why a solution of 0.10 M HNO(ag) conducts more electrical current than does a solution of 0.10 M formic acid, HCOOH. 2. Explain the observed trend in melting points in the hydrogen halides. HI HBr 88.5 °C HF 83.1 "C 14.8° Ethanol has a heat of vaporization of 38.56 kJ/msol and a normal boiling point of 78.4°C. what is the vapor 3. pressure ofethanol at 15 ℃ ? 4. One type of household bleach contains 455% sodium hypochlorite(NaOCl)...