Question

At a certain temperature, this reaction establishes an equilibrium with the given equilibrium constant, Ke 3 A(g) + 2B() 4C(g) K -1.33 x 1015 If, at this temperature, 1.30 mol of A and 3.80 mol of B are placed in a 1.00 L container, what are the concentrations of A, B, and C at equilibrium? (A) = 0.01 [B] - 2.94 (C) = 1.72

the hints say use a reverse reaction and find the concentration of A. i did this. and i dint know how to go furthur

Answer 1

Since value of equilibrium constant is very high , it can be assumed that reaction is complete. Since one of the reactant will be limiting, in this case it is A , we will calculate its concentration by equilibrium expression.
Let moles of A at equilibrium are x .
32 2 + س عبا 308 w ۰۱ :O 1.3 we 1 x ام (3*3 - 3 . 8 پا 103 ty knol 2.93 mol 2.6 mod رم :ہوا [2] (5) ارمی. 2) : (2013) برق - 033 * (( -کے 3 ی 32 گ 16 × . 33 کا۔ ر کر 16 * ہا az 1.58 x 10 m

M S6, (A - * - ( T8 * 16 Try) - 2.93 M Pc ) - 2 - 6 M