How long (in seconds) would it take for the concentration of A to decrease from 0.680 M to 0.200 M?

For first order reactions
[A] = [A0]*exp(-k*t)
if K = 0.18
how long in s for 0.68 to 0.20
[A] = [A0]*exp(-k*t)
0.20 = 0.68*exp(-0.18*t)
t = 6.79 s
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Question 13 of 15 Submit How long will it take for the concentration of A to decrease from 1.25 M to 0.205 for the second order reaction A → Products? (k = 1.52 M-'min-)