Homework Answers
here,
q1 = - 2q is at x1 = 0 m
q2 = 5 q is at x2 = 1 m
a)
the value of x between (-1m) to 0 m for potential be zer0
V = k * (-2q)/x + k * (5q)/(x + 1)
0 = - 2 /x + 5 /(x+1)
solving for x
x = 0.67 m
the value of x is -0.67 m
b)
the potential is greater when go left from -1 m
c)
the electric potential at x = -5 m , V = k * (-2q)/5 + k * (5q)/(5 + 1)
V = ( 9 * 10^9 * 3.67 * 10^-9) * ( - 2/5 + 5/6)
solving for V
V = 14.3 V
the electric potential at x = -5 m is 14.3 V
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Predict/Calculate Problem 20.34 In (Figure 1 the charge q 3.67 x 10 9 C.
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In the figure, charge q 1 = 2.4 × 10-6 C is placed at the origin...
In the figure, charge q 1 = 2.4 ×
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In (Figure 1), the charge q= 5.07 x 10^-9 C. Find the value of
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the positive x-axis can a third charge Q = -8.3 µC be placed such
that the resultant force on this third charge is zero?
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x-axis, at x = -0.20 m. Where along the positive
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