Solution to example 8.46
Let U = 2Y/θ and let mY(t) denote the mgf for the exponential distributio with mean θ.
A) mU(t) = E(etU) = E(et2Y/θ) = mY(2t/θ) = (1- 2t)-1
This is the mgf for the chi-square distribution with one degree of freedom.
U has this distribution since mgfs are unique and since the distribution does not depend on θ, U is a piotal quantity.
B) The chi-square table with 2 degrees of freedom tells us that P(.102587 < 2Y/θ < 5.99147) = .90
SO (2Y/5.99147, 2Y/.102587) respresents a 90% confidence interval for θ.
Complimentary answer:
C) My guess is that they are the same but not sure.
Please give thumbs up to my answer...
Reference: G2. This is a continuation of Exercise 8.46. (d) Use the pivotal quantity 2ye to...
Use the problem in 8.28 to construct a 90% confidence interval
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